Colleague's watch dropped from a table. Face down.
Ouch ....
Will send in to Ball service center, most probably the movement need to be clean as well.
Let's do some simple physics (my first attempt after 23 years)......
Assuming the watch weighs 200g or 0.2kg
Force = mass x acceleration
F= 0.2kg x 10m/s2
F= 2N
The watch fell on its face. I assume the diameter of the dial / crystal is 40mm. Hence the radius is 20mm or 0.02m. Area of the dial / crystal is therefore approx 3.1416 x 0.02m x 0.02m = 0.001256 metre squared.
Pressure exerted ==> P = F/A = 2/0.001256 = 1,592.3 Pascal = 1.5923kPa.
Now, from my memory, 1 ATM is 101.3kPa.
Can 1% of the atmosphereic pressure really crack the crystal like that? Or maybe my physics is rusty beyond help?